Homework SourseA random sample of n 4 scores is obtained from a normal pop
A random sample of n = 4 scores is obtained from a normal population with m=20 and theta=4. what is the probability of obtaining a mean greater than M=22 for this sample?
A. 1.00
B. 0.3085
C. 0.1587
D. 0.50
Please explain ty
A random sample of n = 4 scores is obtained from a normal population with m=20 and theta=4. what is the probability of obtaining a mean greater than M=22 for this sample?
A. 1.00
B. 0.3085
C. 0.1587
D. 0.50
Please explain ty
A random sample of n = 4 scores is obtained from a normal population with m=20 and theta=4. what is the probability of obtaining a mean greater than M=22 for this sample?
A. 1.00
B. 0.3085
C. 0.1587
D. 0.50
Please explain ty
Solution
z = (X-Mean)/(S.D/sqrt n)
z = (22-20)/(4/sqrt 4) = 1
1-0.8413=0.1587
Letter C
