Using python write a program able to a Euclid Archimedes N

Using python, write a program able to:

a = [ \"Euclid\", \"Archimedes\", \"Newton\",\"Descartes\", \"Fermat\", \"Turing\", \"Euler\", \"Einstein\", \"Boole\", \"Fibonacci\", \"Nash\"]

1. Display the longest name

2. Display the shortest name

3. Display a string that consists of the first letter from each of 11 names in the list a

4. Display a string that consists of the last letter from each of 11 names in the list a

5. Ask the user for a letter. Display the number of times the letter appears in the list

6. Sort list a i.e. the first name in the list should be Archimedes; last name is Turing

7. As you process the array make sure you are using a while , for etc loop

i would appreciate if i can get the code

Solution

Here is the main.py code:

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a = [ \"Euclid\", \"Archimedes\", \"Newton\",\"Descartes\", \"Fermat\", \"Turing\", \"Euler\", \"Einstein\", \"Boole\", \"Fibonacci\", \"Nash\"]

longest_name = a[0];
shortest_name = a[0];
first_letter_string = \"\";
last_letter_string = \"\";
user_letter = \'\';

user_letter = raw_input(\"Enter the letter you want to search (If entered more than one, only first character will be considered): \");
user_letter_count = 0;

if len(user_letter) > 1:
user_letter = user_letter[0];

for name in a:
if len(name) > len(longest_name):
longest_name = name;
  
if len(name) < len(shortest_name):
shortest_name = name;
  
first_letter_string += name[0];
  
last_letter_string += name[len(name)-1];
  
if user_letter != \'\':
for char in name:
if user_letter == char:
user_letter_count += 1;

print \"Longest name: \" + longest_name;
print \"Shortest name: \" + shortest_name;
print \"First letter string: \" + first_letter_string;
print \"Last letter string: \" + last_letter_string;

if user_letter != \'\':
print \"Number of times user letter {} appeared is {}\".format(user_letter,user_letter_count);
  
b = a;
b.sort();

print(\"Sorted List: \");
print b;

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