Hi everyone I am curious how you would apply newtons method

Hi everyone,

I am curious how you would apply newton\'s method to solve this differential equation after you have a backwards euler approximation. If you could detail your steps that would be very helpful.

A chemical compound decays over time when exposed to air, at a rate proportional to its concentration to the power of 3/2. At the same time, the compound is produced by another process. The differential equation for its instantaneous concentration is

dn(t) dt = 0.8n 3/2 + 10n1[1 exp(3t)],

where n(t) is the instantaneous concentration, n1 = 2000 is the initial concentration at t = 0. Solve the differential equation to find the concentration as a function of time from t = 0 until t = 0.5 s, using the Backward Euler method. Use a step size of h = 0.002 s and plot n(t) versus t. First clearly write down your finite difference approximation. Note that, you will obtain an ‘implicit’ algebraic equation which you will have to solve iteratively at each time step. Use the Newton’s method for iterative solution. Provide your computer program and clearly indicate your algorithm with sufficient comments on the program. How will you verify that your predicted answer is a reasonable estimate using this particular numerical scheme? Accordingly, verify your answer and show proof.

Solution

n(0.05) = 580.784

h t n(t) n\'(t)
0.002 0 2000 -71554.17528
0.002 0.002 1856.891649 -63893.60258
0.002 0.004 1729.104444 -57281.825
0.002 0.006 1614.540794 -51542.76214
0.002 0.008 1511.45527 -46534.92235
0.002 0.01 1418.385425 -42143.68127
0.002 0.012 1334.098063 -38275.47908
0.002 0.014 1257.547105 -34853.41403
0.002 0.016 1187.840277 -31813.8637
0.002 0.018 1124.212549 -29103.87109
0.002 0.02 1066.004807 -26679.10516
0.002 0.022 1012.646597 -24502.25727
0.002 0.024 963.6420821 -22541.77089
0.002 0.026 918.5585403 -20770.82843
0.002 0.028 877.0168834 -19166.53786
0.002 0.03 838.6838077 -17709.27574
0.002 0.032 803.2652562 -16382.1534
0.002 0.034 770.5009494 -15170.58098
0.002 0.036 740.1597875 -14061.90932
0.002 0.038 712.0359689 -13045.13456
0.002 0.04 685.9456997 -12110.65313
0.002 0.042 661.7243935 -11250.05781
0.002 0.044 639.2242779 -10455.96707
0.002 0.046 618.3123437 -9721.881804
0.002 0.048 598.8685801 -9042.064593
0.002 0.05 580.7844509
Hi everyone, I am curious how you would apply newton\'s method to solve this differential equation after you have a backwards euler approximation. If you could

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