Are the odd real functions a subspace Prove or give countere
Are the odd real functions a subspace? Prove or give counter-example.
Solution
The odd real functions will form a subspace if
a) The zero function must be present in the subspace
b) For function x and y belonging to subspace, (x+y) belongs to subspace
c) For x belonging to subspace, cx will also belong to subspace where c is a constant
Proof of part a
Since 0(x) = 0(-x), where 0 is a zero function
Proof of part b
f(x) = -f(-x)
g(x) = -g(-x)
f(x) + g(x) = -f(-x) - g(-x) = -(f(-x) + g(-x))
Hence the function is an odd function, which will still be present in the subspace
Proof of part C
f(x) = -f(-x)
cf(x) = -cf(-x)
Hence it is also an odd function, therefore belongs to subspace
