If some baseball diamond is a square with 93 feet between th

If some baseball diamond is a square with 93 feet between the bases, how far is the second base from home plate?

Solution

Given the diamound is a square

The hypotenuse is the distance from home to second, or side x.
The legs are from home to first and from first to second.

x^2 = 93^2+93^2

x=sqrt{93^2+93^2}

=sqrt{2}* 93

131.502