Two shuffleboard disks of equal mass one orange and the othe

Two shuffleboard disks of equal mass, one orange and the other yellow, are involved in an elastic, glancing collision. The yellow disk is initially at rest and is struck by the orange disk moving with a speed of 4.00 m/s. After the collision, the orange disk moves along a direction that makes an angle of 38.0degree with its initial direction of motion. The velocities of the two disks are perpendicular after the collision. Determine the final speed of each disk. An unstable atomic nucleus of mass 1.92 times 10^-26 kg initially at rest disintegrates into three particles. One of the particles, of mass 5.19 times 10^-27 kg, moves along the y axis with a speed of 6.00 times 106 m/s. Another particle, of mass 8.49 times 10^-27 kg, moves along the x axis with a speed of 4.00 times 10^6 m/s. Find the velocity of the third particle. Find the total kinetic energy increase in the process.

Solution

call orange disc \'od\' yellow = \'yd\'

Mod = Myd = M

V1od = 4 m/s
V2od = 4 sin 38 in perpendicular and = 4 cos 38 in straight on direction.

conservation of momentum
MVod1 + MVyd1 = MVod2 + MVyd2

M is the same so cancels out

Vod1 + Vyd1 = Vod2 + Vyd2

4 + 0 = (4 sin 38) + Vyd2

Vyd2 = 4 - (4 sin 38) = 1.537 m/s