For the following operation assume the register and memory c

For the following operation assume the register and memory contents are given as fill in the register contents and CCR bits after the operation is complete

Solution

A register contains 80H
B register contains 0FH

MUL B

gives, A*B => 80H * 0FH ==> 0780H

so, A will contains value 80H
and CCR contains value 07H