The sum of nine interior angles of a closedpolygon traverse

The sum of nine interior angles of a closed-polygon traverse each read to the nearest 1\" is 1260° 00\'09\" Part A What is the misclosure? Express your answer as an integer. vec Submit Request Answer ? Part B What correction would be applied to each angle in balancing them using the method below? Applying an average correction to each angle where observing conditions were approximately the same at all stations. Express your answer as an integer vec

Solution

Here

Sum of 9 interier angles is 1260^o00\'09\"

But the sum of interier angles of a polygon with n sides is equal to (n-2)*180^o

Thus for 9 internal angles it should be equal to (9-2)*180^o = 1260^o

PART A

Misclouser = 1260^o00\'09\"- 1260^o = 00^o00\'09\"

PART B

Correction required to each angle = Misclosure/Number of angles = -00^o00\'09\"/9 = -00^o00\'01\"