What is the average shear stress in the internal vertical su
What is the average shear stress in the internal vertical surface AB (or CD), if F = 20 kN, and Are Area(CD) = 1000 mm^2 20 N/mm^2 10 N/mm^2 10 kPa 200 kN/m^2 20 MPa The thrust bearing is subjected to the loads as shown. Determine the order of average normal developed on cross section through B. C and D. C > B > D C > D > B B > C > D D > B > C The center portion of the rubber balloon has a diameter of d = 100 mm. If the air pressure within balloon\'s diameter to become d = 125mm, determine the average normal strain in the rubber. 0.2 0.25 0.25 1.25
Solution
1) Shear stress = Shear force/ Shear Area
Stress= 20000 / (2*1000) N/mm^2 Area undr double shear= 2* area under single shear
Shear Stress= 10Mpa= 10 N/mm^2
The answer is b
2) Stress = Force/ Area
Stress in B= 500/( pi*65^2/4) =0.15068 MPa
Stress in C= 500/(pi*140^2/4) = 0.0325 MPa
Stress in D= 200/(pi*100^2/4) = 0.0255 Mpa
D<C<B
Answer is c
3)
Normal strain= change in dimension/ original dimension
strain = (125-100)/100
strain=25/100=0.25
answer is option c
