The following may involve the use of the sine Rule as well C

The following may involve the use of the sine Rule as well Cosine Rule. In the given ABC, D is a point on [BC] |BD| = 6 cm, |AC| = 9 cm, |

Solution

10. In triangle ADC, <ADC=180-(50+80)=50

Using sine law which is

sin <ADC/AC=sin<DAC/DC

sin 50/6= sin50/DC

DC=6

ii. AB

Using cosine law which is

AB2=AC2+BC2-2 AC BC cos <ACB

AB2= 92+152-2(9)(15)cos80

AB2=81+225 - 270cos 80

AB= 16cm

 The following may involve the use of the sine Rule as well Cosine Rule. In the given ABC, D is a point on [BC] |BD| = 6 cm, |AC| = 9 cm, |Solution10. In triang

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