A veterinarian wants to create a new food mixture for cats w

A veterinarian wants to create a new food mixture for cats with urinary tract disease. The precise level of ash in the felines food is critical in maintaining the health of the cat. The veterinarian mixex 2 foods, A + B. A contains 25% of ash and B contains 15% ash. The resulting mix must contain 20 pounds of ash. How much of food A would be needed if 50 pounds of food B were used in the mixture?

Solution

A contains 25% of ash and B contains 15% ash

Let x poundsof food A is used.

Ash in A = 0.25*x

Ash in B = 0.15*50

The resulting mix must contain 20 pounds of ash

0.25x + 50*0.15 = 20

0.25x = 12.5

x = 12.5/0.25 = 50 pounds of food A