If x is invertible mod n prove that the order of x mod n is
If x is invertible mod n, prove that the order of x mod n is the same as the order of the inverse of x mod n. Use n = 155150096071 and phi(n) = 155148967944 to factor n.
Solution
E6: Let the order of x be n such that xn = e.
Now we need to show that (x-1)n = e
Consider (x-1)n = e (x-1)n
=> (x-1)n = xn(x-1)n
=> (x-1)n = (x x-1)n
=> (x-1)n = en
=> (x-1)n = e
Thus the order of x-1 is n.
Therefore the order of x and its inverse is same.
