2 Consider the functionSolution2A Domain of fx 1Infinity 2B

2. Consider the function

Solution

2A. Domain of f(x) = [1,Infinity)

2B. sqrt (x^2-1) = sqrt(1)

Squaring both sides

x^2-1=1

x^2=2

x=+sqrt(2) & -sqrt(2)

3. 2e^x=1

e^x=1/2

Tanking natural log both sides

ln (e^x) = ln (1/2)

x= ln(1/2)

4. 2 ln (x^2)=1

ln (x^2) = 1/2

Converting to exponential form

x^2= e^(1/2)

x= e^(1/4)

5. log4 5

Converting to base 10

log10 (5) / log10 (4)

log10 (5)/ (2 X log10 (2))

0.698/ (2 X 0.3010)

1.159 Answer

2. Consider the functionSolution2A. Domain of f(x) = [1,Infinity) 2B. sqrt (x^2-1) = sqrt(1) Squaring both sides x^2-1=1 x^2=2 x=+sqrt(2) & -sqrt(2) 3. 2e^x

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