2 Consider the functionSolution2A Domain of fx 1Infinity 2B
2. Consider the function
Solution
2A. Domain of f(x) = [1,Infinity)
2B. sqrt (x^2-1) = sqrt(1)
Squaring both sides
x^2-1=1
x^2=2
x=+sqrt(2) & -sqrt(2)
3. 2e^x=1
e^x=1/2
Tanking natural log both sides
ln (e^x) = ln (1/2)
x= ln(1/2)
4. 2 ln (x^2)=1
ln (x^2) = 1/2
Converting to exponential form
x^2= e^(1/2)
x= e^(1/4)
5. log4 5
Converting to base 10
log10 (5) / log10 (4)
log10 (5)/ (2 X log10 (2))
0.698/ (2 X 0.3010)
1.159 Answer

