Homework SourseFor the following reaction 551 grams of iron are mixed with
For the following reaction, 5.51 grams of iron are mixed with excess oxygen gas . The reaction yields 4.88 grams of iron(II) oxide .
iron ( s ) + oxygen ( g ) ----> iron(II) oxide ( s )
| What is the theoretical yield of iron(II) oxide ?___ | grams |
| What is the percent yield for this reaction ?____ | % |
Solution
2 Fe (s) + O2 (g) -------------> 2 FeO (s)
111.69 g 32 g 143.68 g
5.51 g ??
from the reaction :
111.69 g Fe ------------------> 143.68 g FeO
5.51 g Fe -----------------> ??
theoretical yield of FeO = 5.51 x 143.68 / 111.69
theoretical yield of FeO = 7.09 g
% yield = actual / theretical ) x 100
= 4.88 / 7.08 ) x100
% yield = 68.8 %
