Consider the matrix A 2 1 1 0 4 2 1 2 6 3 2 2 Determine a m
Consider the matrix A = (2 1 1 0 4 2 1 2 6 3 2 2) Determine a maximal linearly independent subset of columns from A.
Solution
We will reduce A to its RREF as under:
Multiply the 1st row by ½
Add -4 times the 1st row to the 2nd row
Add -6 times the 1st row to the 3rd row
Multiply the 2nd row by -1
Add 1 times the 2nd row to the 3rd row
Add -1/2 times the 2nd row to the 1st row
Then the RREF of A is
1
½
0
1
0
0
1
-2
0
0
0
0
Apparently, only the 1st and the 3rd columns of A are linearly independent. Therefore, the maximal linearly independent subset of columns from A is { (2,4,6)T, (1,1,2)T}
| 1 | ½ | 0 | 1 |
| 0 | 0 | 1 | -2 |
| 0 | 0 | 0 | 0 |
