Find the derivative yln4x29xSolution The derivative of lnx i
Find the derivative.
y=ln|4x^(2)-9x|
y=ln|4x^(2)-9x|
Solution
The derivative of ln(x) is 1/x. Basically, you\'re taking the recipricol of whatever is in the brackets. You then multiply 1/x with the derivative of x, which is 1. For this example, first take the derivative of |4x^(2)-9x| = |8x - 9| Multiply |8x - 9| by 1/|4x^(2)-9x| = |8x - 9| / |4x^(2)-9x| Hope this helps! :-)