31 4log2 2 512 Solution314 log122 we have to use the followi

31. -4log,2 2 512

31.-4 log₁₂2

we have to use the following rule

a log b= log b^a

so we get -4 log₁₂2= log₁₂2^-4= log₁₂(1/16)

b.-1/3 log₂125 = log₂5^3*-1/3= log₂(1/5)

31. -4log,2 2 512 Solution31.-4 log122 we have to use the following rule a log b= log ba so we get -4 log122= log122-4= log12(1/16) b.-1/3 log2125 = log253*-1/

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