A daring 510n swimmer drives off a cliff with a running hori

A daring 510-n swimmer drives off a cliff with a running horizontal loap, as shown in the figure What must her minimum speed be just as she leaves the top of the cliff so that she will miss the ledge at the bottom, which is 1.75 m wide and 9.00 m below the top of the cliff?

Solution

initial speed = Vo

Y = Uyt - 0.5gt^2

x = Ux*t

-9 = 0 -0.5*9.8*t^2

t = 1.35 s

x = Vo*t

Vo = x/t

Vo = 1.75/1.35 = 1.291 m/s

the horizontal speed of the diver is 1.291 s