Hi I am having trouble with these questions Could you please

Hi I am having trouble with these questions.. Could you please write out the steps to solve them?

Find the vertical and the horizontal shits

The graph of y=(x3)2+10 is the graph of y=x2+10

The graph of y=3(x5)2(x5)+13 is the graph of y=3x2x+10

Find the inverse for each of the following functions.

g(x)=2x34

h(x)=7x+4

The graph of y=(x3)2+10 is the graph of y=x2+10

Notice that x has been replaced by x-3.
So, when x is replaced by x-a, it signifies a RIGHT SHIFT by a
So, shifted right by 3 units

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The graph of y=3(x5)2(x5)+13 is the graph of y=3x2x+10
Well, we can write that as
[3(x - 5)^2 - (x - 5) + 10] + 3

Notice that all x\'s are replaced by x-5\'s
and then 3 is added at he end

Clearly a RIGHT SHIFT by 5 units and a SHIFT UPWARD by 3

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2x^3 - 4

Step 1: y = 2x^3 - 4

Step 2 : Interchange x and y
x = 2y^3 - 4

Step 3: Solve for y from step 2
x + 4 = 2y^3
y^3 = (x + 4)/2
y = cbrt((x+4)/2)

So, the inverse is
cuberoot((x+4)/2)

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7x + 4

y = 7x + 4

x = 7y + 4

x - 4 = 7y
y = (x - 4)/7

So, the inverse is :

h^-1(x) = (x - 4)/7