find the amplitude period and phase shift of 1gtheta 3sint

find the amplitude , period, and phase shift of

1.g(theta) = -3sin(theta -2pi)

2.g(theta)= -17sin(3theta +pi/4)

3.g(theta)=-tan(2theta -pi)

Solution

1. g(theta)=-3sin(theta-2pi)

this is of the form

y=Asin(Bx-C)

amplitude,A=3

period=2pi/B=2pi

phase shift=C/B=2pi/1=2pi

2.g(theta)=-17sin(3theta+pi/4)

amplitude,A=17

period,2pi/B=2pi/3

phase shift=-C/B=-pi/4/3=-pi/12

3.g(theta)=-tan(2theta-pi)

amplitude,A=1

period=pi/B=pi/2

phase shift=C/B=pi/2

find the amplitude , period, and phase shift of 1.g(theta) = -3sin(theta -2pi) 2.g(theta)= -17sin(3theta +pi/4) 3.g(theta)=-tan(2theta -pi)Solution1. g(theta)=-

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