find the amplitude period and phase shift of 1gtheta 3sint
find the amplitude , period, and phase shift of
1.g(theta) = -3sin(theta -2pi)
2.g(theta)= -17sin(3theta +pi/4)
3.g(theta)=-tan(2theta -pi)
Solution
1. g(theta)=-3sin(theta-2pi)
this is of the form
y=Asin(Bx-C)
amplitude,A=3
period=2pi/B=2pi
phase shift=C/B=2pi/1=2pi
2.g(theta)=-17sin(3theta+pi/4)
amplitude,A=17
period,2pi/B=2pi/3
phase shift=-C/B=-pi/4/3=-pi/12
3.g(theta)=-tan(2theta-pi)
amplitude,A=1
period=pi/B=pi/2
phase shift=C/B=pi/2
