Solve the problem 9 A wheel is rotating at 5 radianssec and

Solve the problem. 9) A wheel is rotating at 5 radians/sec, and the wheel has a 83-inch diameter. To the nearest 9) foot, what is the speed of a point on the rim in ft/min? A) 1033 ft/min B) 1028 ft/min C) 1038 ft/min D) 1043 ft/min Approximate the length using the formula for arc length. Round to the nearest meter. 10) A television tower 540 m high subtends an angle of 3°50. How far away is the tower? 10) A) 8111 m B) 8071 m C) 4860 m D) 4900 m SHORT ANSWER. Write the word or phrase that best completes each statement or answers the questlon Find the value of s in the Interval [0, T/2] that makes the statement true. Round to four decimal places. 11) sec s 3.7404 Solve the problem. 12) Each tire of an automobile has a radius of 1.25 feet. How many 12) revolutions per minute (rpm) does a tire make when the automobile is traveling at a speed of 115 feet per sec? Round your answer to the nearest tenth. 13) A center-pivot irigation system waters a sector-shaped field. Find the 13 area of the field if the central ogle. e-44° ad the radius, r 148 meters. Round to the nearest whole number Find the exact value without using a calculator 3n 14 sec Solve the problem. 15) A sensor ight instaled on the edge of a home con detect motion for a 15) distance of 69 ft. in front and with a range of motion of 262. Over what area will the sensor detect motion and become illuminated? Round to the nearest hundredth. 16) The maximum afternoon temperature in Granderson is modeled by 16) 62. 30 cos--where t represents the maximum afternoon temperature in degrees Fahrenheit in month x with xOrepresenting January. x representing February, and so on. Find the maximum aftemoon temperature in June. 17) Through how many radians will the hour hand on a clock rotate in24 17) hours? (Using a twelve hour clock Find the exact value of s in the given interval that has the glven circular function value. 18) 3m

Solution

9) radius = 83/2

speed = angular velocity * radius

= 5* 83/2

= 415/2 inches / sec

converting it to feet / sec

415/2 * 60/12

= 1037.5

or 1038 ft / min

option c is correct

10)

let distance = x

tan 3 degrees 50\' = 540 / x

x = 8071

tower is 8071 m