Use natural log to solve 2e to exp 7x66 XSolution2e7x 6 6

Solution

2e^(7x + 6) = 6

e^(7x + 6) = 6/2

e^(7x + 6) = 3

ln e^(7x + 6) = ln 3

(7x + 6) ln e = ln 3

7x + 6 = ln 3

7x = ln 3 - 6

x = (ln 3 - 6)/7

If you receive more than one answer, rate the best answer first.

Rating encourages experts to continue helping you.