Consider the following reaction NOCLg NOg Cl2l If the initi

Consider the following reaction: NOCL_(g) <-> NO_(g) + Cl_2(l). If the initial concentration of NOCL_(g) is 4 M, the equilibrium concentration of NO_(g) is 1.32 M at a certain temperature. The K_c at this temperature is?

Solution

                     2NOC_lg) <-> 2NO_(g) + Cl_2(l)

I                    4                     0          0

C               -2*0.66              2*0.66      0.66

E                2.68                 1.32       0.66

       kc   = [NO]^2[Cl2]/[NOCl]^2

            = (1.32)^2 *0.66/(2.68)^2   = 0.16 >>>>answer