apling Learning Write the balanced neutralization reaction b

apling Learning Write the balanced neutralization reaction between H2SO4 and KOH in aqueous solution. Phases are optional. 0.850 L of 0.430 M H SO4 is mixed with 0.800 L of 0.280 M KOH. What concentration of sulfuric acid remains after neutralization? M H,SO Previous Give Up & View Souton Check Answer ·Next Eut 8o 2 3 4 6 8

Solution

balanced equation is

H₂SO₄ + 2 KOH -----> K₂SO₄ + 2 H₂O

Number of moles of H2SO4 = molarity * volume of solution in L

Number of moles of H2SO4 = 0.430 * 0.850 = 0.366 mol

Number of moles of KOH = 0.280 * 0.800 = 0.224 mole

from the balanced equation we can say that

2 mole of KOH requires 1 mole of H2SO4 so

0.224 mole of KOH will require 0.112 mole of H2SO4

number of moles of H2SO4 left = 0.366 - 0.112 = 0.254 mole of H2SO4

total volume of solution = 0.800 + 0.850 = 1.65 L

Moalrity = 0.254 / 1.65 = 0.154 M

Therefore, moalrity = 0.154 M