If 040 g of solid NaOH is added to 10 liter of a buffer solu

If 0.40 g of solid NaOH is added to 1.0 liter of a buffer solution that is 0.10 M in CH3COOH and 0.10 M in NaCH3COO, how will the pH of the solution change?

Solution

The change in pH = log [NaCH3COO]/[CH3COOH]=0.0871