Let Z N01 Find the following probabilities a P0

Let Z ~N(0,1). Find the following probabilities:

a) P(0<Z<1.34)

b) P (-1.23 < Z<3.45)

c) P(Z>1.23)

d) P(Z<2.46)

Solution

using tables of normal distrbiution

a)

P( 0<z<1.34) = 0.5 - 0.0901 = 0.4099

b)

P8 -1.23 <z< 3.45) = 1 - 0.1093 - 0.00028 = 0.89042

c)

P(z > 1.23) = 0.1093

d)

P( z<2.46) = 1 -0.00695 = 0.99305