In order to hold the wheelbarrow in the position shown force

In order to hold the wheelbarrow in the position shown, force F must produce a counterclockwise moment of 200 N.m about the axle at A. Determine the required magnitude of force F.

Solution

Here, resolving force F into its horizontal and vertical components.

Further, applying the principle of moments -

M(A) = 200 = F sine(30) * (1.5) + F cos(30) * (1.15)

=> 200 = F*[0.75 + 0.996] = 1.746 * F

=> F = 200 / 1.746 = 114.54 N