Question Help The owner of two fast food restaurants has rec
Solution
a)
FOR RESTAURANT A:
Thus,  
   
 Mean = Sum(xf) / Sum(f) =    3.7625 [ANSWER, MEAN FOR RESTAURANT A]
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FOR RESTAURANT B:
Consider:
Thus,  
   
 Mean = Sum(xf) / Sum(f) =    2.9 [ANSWER, MEAN FOR RESTAURANT B]
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b)
FOR RESTAURANT A:
Thus,  
Variance = [Sum(x^2f) - Sum(xf)^2/Sum(f)]/[Sum(f)-1] = 1.347943038
Standard deviation = sqrt(Variance) = 1.161009491 [ANSWER, STANDARD DEVIATION FOR RESTAURANT A]
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FOR RESTAURANT B:
Thus,  
   
 Variance = [Sum(x^2f) - Sum(xf)^2/Sum(f)]/[Sum(f)-1] =    1.946376812
 Standard deviation = sqrt(Variance) =    1.395126092 [ANSWER, STANDARD DEVIATION FOR RESTAURANT B]
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c)
As we can see, restaurant A has a higher mean rating, and it is more consistent as well, as it has lower standard deviation. [ANSWER]
| x | f | x f | x^2 f | 
| 1 | 3 | 3 | 3 | 
| 2 | 13 | 26 | 52 | 
| 3 | 8 | 24 | 72 | 
| 4 | 32 | 128 | 512 | 
| 5 | 24 | 120 | 600 | 

