Refrigerant 134a is compressed with no heat transfer in a pi
Refrigerant 134a is compressed with no heat transfer in a piston–cylinder assembly from 30 lbf/in.2, 20°F to 120 lbf/in.2 The mass of refrigerant is 0.04 lb. For the refrigerant as the system, W = –0.56 Btu. Kinetic and potential energy effects are negligible. Determine the final temperature, in °F.
Solution
From !st law of thermodynamics
dQ=dU+dW
dQ=0 no heat transfer
therfore dU= -dW
U2-U1= 0.56\\0.04 Btu/lb
U2= 14+U1
now at 30psi,20F U1=97.6 btu/lb
U2=97.6+14=111.6 btu/lb
therefore at U2, 120psi
Temperature = 114 F

