Use the given conditions to write an equation for the point

altlohs to White an equation for the line in point-slope nt (5, 2) and perpendicular to the line y 4x t 6.

Solution

for perpendicular lines,

m1*m2 = -1

m = slope of line

for line

y = 4x + 6

y = mx + c

m1 = slope of above line = 4

So the slope of new line will be

m2 = -1/m1 = -1/4

this new line goes through (5, 2)

So, slope-point equation of line is

(y - y1) = (m)*(x - x1)

Here

(y - 2) = (-1/4)*(x - 5)

y = -x/4 + 5/4 + 2

y = -x/4 + 13/4