For the reaction shown find the limiting reactant for each o

For the reaction shown, find the limiting reactant for each of the following initial amounts of reactants.

4Cr(s)+3O2(g)===>2Cr2O3

Solution

Part A
Cr =1 mole and o2= 1 mole
to get limiting reactant, divide no. of moles by its stiochoimetric coefficient. the one with less value will vanish first,thus limiting reactant.
In 1st part, 1/4 < 1/3.
Thus, Cr is the limiting reactant.
I hope this will help.