26 Given the density of Au is 193 gcm3 determine the mass of

26) Given the density of Au is 19.3 g/cm3, determine the mass of gold (in grams) in an ingot with the dimensions of 10.0 in × 4.00 in × 3.00 in. A)3.80 × 104 B) 102 C)2.32 × 103 D) 0.6 E) none of the above

Solution

Density of Au = 19.3g/cm^3

ingot volume = 10 * 4 * 3 in^3 = 120 in^3

ingot volume = 120 *(2.54cm)^3 (since 1 in = 2.54 cm)

ingot volume = 1966.4477 cm^3

1 cm^3 volume has 19.3 g

1966.4477 cm^3 volume has 19.3 * 1966.4477 g

mass of gold ingot = 37952 g = 3.8 * 10^4 g

Answer : A