1 Given the following reaction 3CaNO32 2Li3PO4Solutioneffec

1. Given the following reaction:

3Ca(NO₃)₂ + 2Li₃PO₄

Solution

effective moles of cano32=2*3.4

=6.8

effective moles of lino3=2.4*3

=7.2 moles

so the limitimg reagent is Ca(NO3)2

so moles of Li(NO3) formed=2*3.4

=6.8

so mass of Li(NO3)

=69*6.8

=469.2 grams

so percent yeild=452*100/469.2

=96.33 %