A Ferris wheel has a radius of 428 feet The bottom of the Fe

A Ferris wheel has a radius of 42.8 feet. The bottom of the Ferris wheel sits 0.5 feet above the ground. You board the Feris wheel at the 6 oclock position and rotate counter-clockwise. a Define a function, / that gives your height above the ground (in feet) in terms of the angle of rotation (measured in radians) you have swept out the 6 o\'clock position, a ta)-42Bsina) 434Preview Define a function, g, that gives your height above the ground (in feet) in b. o\'clock position, s s)-42.8sn(a) Preview License Points possible: 1 Unlimited attempts. tn crre in oradebook:0

Solution

a)

since the boarding point of ferris wheel starts at lowest point(6 o\'clock position)

f(a)= (-42.8cos(a)) +(42.8+0.5)

=>f(a)= -(42.8cos(a)) +43.3  

b)

s=42.8*a

=>a=s_/42.8

=>g(s)= -(42.8cos(s_/42.8)) +43.3  

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or else you can use

f(a)= 42.8sin(a-(_/2)) +43.3  

g(s)= -42.8sin((s_/42.8)-(_/2)) +43.3