The parachute on a race car of weight 8140 N opens at the en

The parachute on a race car of weight 8140 N opens at the end of a quarter mile run when the car is traveling at 33.4 m/s. What total retarding force must be supplied by the parachute to stop the car in a distance of 1030 m?

Solution

Initial Speed of Car = 33.4 m/s
Distance = 1030 m
Final speed of the car = 0

V^2 = u^2 + 2*a*s
0 = 33.4^2 - 2*a*1030
a = 0.54 m/s^2

We know,
F = m * a
F = (8140/9.8) * 0.54 N
F = 448.5 N
Retarding force must be supplied by the parachute to stop the car F = 448.5 N