A 7 kg object is given a displacement s 6m i 2m j 4m k al

A 7 kg object is given a displacement

s = (6m) i + (2m) j + (-4m) k

along a straight line. During the displacment, a constant force of

F = (4N) i + (-2N) j + (3N) k

acts on the object

I already found the work done by F of the displacement, which i got is 8 Joules. I need help finding the component of F in the direction of this displacement.

Solution

Required compnent = F.s/|s| = 8/sqrt(36+4+16) = 8/sqrt(56) = 1.069