What is the value of K such that the curve yx3 kx has a poin

What is the value of K such that the curve y=x^3 -(k/x) has a point of inflection at x=1 Give full working and explination

y=x^3 -(k/x)

y \' = 3x^2 + (k/x^2)

y \" = 6x -(2k/x^3)

For inflection points, y \" =0

=> 6x - (2k/x^3) =0

=> 2k/x^3 = 6x

=> k/x^3 = 3x

=> k = 3x^4

The inflection point is at x=1

so, k = 3* 1^4 = 3