3 a Calculate the electric force Fe between a stationary pro

3. a) Calculate the electric force Fe between a stationary proton and Uranium nucleus . . . separated by a distance of 3.6 nm: {Consider the Uranium nucleus a point charge} b) Is this force repulsive or attractive? WHY? c) Determine the initial acceleration of the proton:

Solution

Answer:

a) Electric force is given by

F = k*q1*q2/d^2

where

q1= 1.6*10^-19 C

q2= 92*1.6*10^-19 C

d = 3.6 nm

F = 9*10^9*(1.6*10^-19 C * 92*1.6*10^-19 C)^2/(3.6*10^-9 m)^2

F= 163.56 * 10^-11 N

b) Force is repulsive bcause like charges repel each other and opposite charges attratcs.

Here both proton and Uranium nuckei are positively charged.

c) Initial accn of thr proton a

F=q E

=> E= 163.56 * 10^-11 N / 1.6*10^-19 C

=> E= 102.225 * 10^8 N/C

F = ma

=> a = 163.56 * 10^-11 N /(1.67x10^-27 kg)

=> a = 97.94 * 10^16 m/s^2