Need some help with my homework Please explain in detail the

Solution

1)

after striking the bullet , the block will start rotating about it\'s centre of mass of system ,

hence , the best arrow is

c) as the centre of mass has onle linear velocity

2)

for the inelastic collision

as speed at the bottom = sqrt(2*g*h)

using conservation of momentum

m * sqrt(2 *g * h1 ) = 2m * sqrt(2* g * h2)

2*g * h1 = 4 * 2 * g * h2

h2 = h1/4

option d)
3)

Using conservation of momentum

(m + 0.5 * m ) * vf = m*v - 0.5 * m * 2v

vf = 0

hence , the option a)