A 11 N horizontal force pushes a block weighing 48 N against

A 11 N horizontal force pushes a block weighing 4.8 N against a vertical wall (see the figure). The coefficient of static friction between the wall and the block is 0.70, and the coefficient of kinetic friction is 0.36. Assume that the block is not moving initially, Will the block move? (\"yes\" or \"no\") In unit-vector notation F_xi+F_yj, what is the force on the block from the wall? Number I+ j units

Solution

a) No,

b)

Let:
P be the applied horizontal force,
R be the normal reaction of the wall,
F be the upward friction force on the block,
W be the weight of the block.

For horizontal equilibrium:
R = P

For vertical equilibrium:
F = W

The force on the block from the wall is:
Ri + Fj
= -Pi + Wj
= -11i + 4.8j.