Two positive point charges are 30 cm apart If the electric p

Two positive point charges are 3.0 cm apart. If the electric potential energy is 82 J , what is the magnitude of the force between the two charges? Express your answer using two significant figures.

V = 82x10^-6 J
d = 3x10^-2 m
The potential energy between two charges V 1/d
The force between two charges F 1/ d^2

F = V/d = (82/3)x10^-4 =27.33x0^-4 N

Ans- Magnitude of the force between the two charges is 27.33x0^-4 N