How many mL of 01201 M NaOH is required to titrate 02191 g o

How many mL of 0.1201 M NaOH is required to titrate 0.2191 g of KHP?

Solution

Applying equivalent concept we can say that

Equivalent of KHP=Equivalent of NaOH

Equivalent of KHP=given weight/equivalent weight

Equivalent weight=molar weight/n-factor=71/1

Equivalent of KHP=0.2191/71

Equivalent of NaOH=molarity×volume×n-factor=0.1201×V×1

Volume of NaOH required=0.0257L=25.7 mL