Homework SourseA A square shaped 45 mm by 45 mm metal rod has resistance o
A). A square shaped ( 4.5 mm by 4.5 mm) metal rod has resistance of 1.19 ohm. The resistivity of material is 0.5* 1.19 *10^-6 ohm-m. What is the length of the rod in meter?
B). Two circular metal plates, separared by a distance 8.85 mm forms 50 nF capacitance. The space between the plates are filled with Tefflon material with epsilon_r = 2.2. Calculate the area of each plate.
A). A square shaped ( 4.5 mm by 4.5 mm) metal rod has resistance of 1.19 ohm. The resistivity of material is 0.5* 1.19 *10^-6 ohm-m. What is the length of the rod in meter?
B). Two circular metal plates, separared by a distance 8.85 mm forms 50 nF capacitance. The space between the plates are filled with Tefflon material with epsilon_r = 2.2. Calculate the area of each plate.
B). Two circular metal plates, separared by a distance 8.85 mm forms 50 nF capacitance. The space between the plates are filled with Tefflon material with epsilon_r = 2.2. Calculate the area of each plate.
Solution
here,
A)
area of the rod , a = 4.5^2 * 10^-6 m
resistance , r = 1.19 ohm
resistivity , p = 0.5 * 1.19 * 10^-6 ohm m
let the length of rod be l
p*l/a = r
0.5 * 1.19* 10^-6 * l/( 4.5^2 * 10^-6) = 1.19
l = 40.5 m
length of rod is 40.5 m
B)
sepration between the plates , d = 8.85 * 10^-3 m
capacitance , C = 50 * 10^-9 F
k = 2.2
let the area of each plate be a
k * epsilon0 * a /d = C
2.2 * 8.85 * 10^-12 * a /( 8.85 * 10^-3) = 50 * 10^-9
a = 22.73 m^2
the area of each plate is 22.73 m^2
