such as find an antiderivative for 3sinx and and e 3x and i
Solution
a) [1 to 2] x dx = [1 to 2] x2/2 since xn dx = xn+1/(n +1)
= (2)2/2 - (1)2/2 = 1/2
b) [0 to /2] 2 d = [0 to /2] 3/3
= (/2)3/3 - (0)3/3
= 3/24
c) [0 to 2] 3x2 + x - 5 dx
= [0 to 2] 3x3/3 + x2/2 - 5x
= [0 to 2] x3 + x2/2 - 5x
= (23 + 22/2 - 5(2)) - (03 + 02/2 - 5(0))
= 0
d) [0 to b1/3] x2 dx
= [0 to b1/3] x3/3
= ((b1/3)3/3) - (03/3)
= b/3
e) [0 to 1/2] 4/(1 -x2) dx
= [0 to 1/2] 4sin-1x since 1/(1 -x2) dx = sin-1x
= 4[sin-1(1/2) - sin-1(0) ]
= 4[/6 - 0]
= 2/3
f) [2 to -4] x-1 dx
= [2 to -4] x-1+1/(-1+1)
= [2 to -4] x/()
= (1/)((-4) -(2))
