An ideal gas is compressed isobarically from 872 m3 to 541 m

An ideal gas is compressed isobarically from 8.72 m^3 to 5.41 m^3 at a pressure of 2.01 times 10^5 Pa due to the addition of 4.35 times 10^5 J of heat. What is the change in the internal energy of the gas? Express your result in scientific notation and to three significant digits.

W=Pdv = 2.01*10^5(8.72-5.41) =6.6532*10^5J

Change in internal energy = 6.6531-4.35)*10^5J = 2.30*10^5J