A 903 g mass of aluminum is formed into a right circular cyl

A 90.3 g mass of aluminum is formed into a right circular cylinder, shaped so that its diameter equals its height. Calculate the resistance between the top and bottom faces of the cylinder. (in ohm)

Solution

density of aluminium is 2.7g/cm^3

therefore

90.3 = 2.7 x pi x D^2 /4 x D

D = 3.492cm

D = 0.03492m

NOW resistance

R = resistivity x L/A

R = resistivity x D / 0.25xpixD^2

R = 0.000000966 ohm