Homework SourseCalculate the DH for the reaction Below I got the answer B b
Calculate the DH for the reaction Below. I got the answer B but the correct answer is E apparently. Don’t know how to get there.
21. Calculate AH°o for the reaction below. 12NH3(g) (kl/moDiL(-45.9) )-4,650 kJ 8HNOg(1) 8(-13394(91.3) 4N0(g) 14H20(g) (4241.8) + 21O2(g) + + o a. +3,540 kJ c. -2,259 kJd. - 4270kJ e. -3,540 kJ SSo. 6 Solution
Ans e) -3540 KJ
The enthalpy of the reaction is given as the difference of the sum total of product formation enthalpy and the sum total of reactant formation enthalpies.
So here it will be given as :
Delta H = 14(-241.8) + 4(91.3) + 8(-133.9) - 12(-45.9) -0
= -3540 KJ
