An object located 340 cm in front of a lens forms an image o

An object located 34.0 cm in front of a lens forms an image on a screen 8.10 cm behind the lens. (a) Find the focal length of the lens. cm (b) Determine the magnification. x (c) Is the lens converging or diverging? diverging converging

Solution

u = -34 cm

v = 8.1 cm

a) 1/f = 1/v - 1/u

=> f = uv/(u - v) = (-34) x 8.1/(-34 - 8.1) = 6.5416 cm

b) m = v/u = 8.1/(-34) = -0.238235

c) converging


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