A squirrel has x and ycoordinates 10 m 34 m at time t10 a

A squirrel has x- and y-coordinates ( 1.0 m , 3.4 m ) at time t1=0 and coordinates ( 5.9 m , -0.50 m ) at time t2 = 3.4 s . For this time interval, find the x-component of the average velocity. For this time interval, find the y-component of the average velocity. Find the magnitude of the average velocity. Find the direction of the average velocity.

Solution

given at t1 = r1 = (x1,y1) = (1 , 3.4) m

at t2 = r2 = (x2,y2) = (5.9 , -0.5) m

Velocity avg of x = (x2-x1)/(t2-t1)

Vx avg = (5.9 - 1)/(3.4 -0)

Vx avg = 1.44 m/s (answer)

Vy avg = (y2-y1)/(t2-t1)

Vy avg = (-0.5 -3.4)/(3.4-0)

Vy avg = -1.14 m/s (answer)

magnitude of avg velocity V^2 = vx^2 + vy^2

Vavg^2 = (1.44^2 + (-1.14)^2

Vavg = 1.835 m/s (answer)

direction tan theta = Vy/vx

tan theta = -1.14/1.44

tan theta = -38.34 deg (answer)